Labor Day is not a good sports-on-TV holiday.
Everyoneâs at the pool getting in one last swim before it closes.
The list of things I âshouldâ do to control my blood pressure would require about 3 hours a day. The list is also contradictory:
- âDo all these things.â
- âAvoid trying to do too much.â
Or
A. Lose weight.
B. Focus on things you can control.
At least I have the âlimit alcoholâ and âquit smokingâ steps down.
Also my approach to trying to reduce my blood pressure probably says something about why I have high blood pressure.
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Seems like a decent enough thread for this.
One that followed in my âfeedâ:
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When I see something claiming ânever before or again in historyâ I get skeptical.
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Remember all of the Facebook memes claiming that we should live it up because for the first time ever the next month will have five Fridays AND five Saturdays AND five Sundays and that wonât happen again until the year 4923 or something equally ridiculous.
Uh, that happens every time a 31-day month starts on a Friday, which is roughly 1/7 of the time. 
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And in general, you can âreuseâ the same calendar every 6, 11, or 28 years based on the following algorithm:
- Divide the year by 4 and take the remainder
- Use the following algorithm to determine the number of years to add/subtract:
** 1 â 6 years
** 2 â 11 years
** 3 â 11 years
** 0 (leap year) â 28 years
** 0 (non leap) â 6 years
E.g., you can take a 2012 calendar; âchangeâ the year to be 2023, and it should be spot on to use as a calendar.
A more accurate algorithm to capture all cases can be found here (look at the second âpostâ answering the question).
At most, youâd only have to wait 40 yearsâbe an interesting exercise to show this given that there are only 14 total calendar patterns to use.
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I just saw a guy walking down the street twirling a pizza dough. Random.
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I went to a a soccer match:Atlanta vs Toronto. Saw a guy there wearing a Sandy Koufax Dodgers shirt and a NY Mets hat. Why? Guy was definitely not alive to see Koufax pitch.
Not really into numerology or number theory
2012 was a leap year and doesnât work for 2023, but my paper planner friends say 2017 works for 2023. And I guess it fits the algorithm.
I guess that algorithm doesnât have an easily-identified inverse element.
So itâs present form is âforward lookingâ . . .
Revised algorithm:
- Divide the year of interest by 4 and take the remainder
- Use the following chart to determine the number of years to add to get the next occurrence:
| Remainder | Add to get next year |
|---|---|
| 1 | 6 |
| 2 | 11 |
| 3 | 11 |
| 0 (leap year) | 28 |
| 0 (non leap) | 6 |
I tried to get the âinverse,â but itâs not as easily displayed given that the earlier year might be a leap year and creates some quirky descriptions.
I think youâre making it too hard. I think you were taking the last digit of 2012 (2) looking up 2 in the algorithm, and adding 11.
But thatâs not the algorithm. The algorithm is to take the remainder when dividing by 4.
For 2012 thatâs not 2, itâs 0.
You add 28 years. That works. Algorithm is fine.
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I am tempted to cross-post in the innumeracy thread, however! 
No. Iâm very familiar with âclock arithmeticâ and now that the remainder of 2012 mod 4 is zero.
I was originally looking to see what prior year calendar to use for 2023. This number has a remainder of 3 and hence subtracted 11 to get the year to useânot looking to see if the âforwardâ direction would still hold. (Hence my statement about inverses not being âsimpleâ in this calculation.)
But I think the âinverseâ operations are as follows:
+ 6 <==> -11
+11 <==> - 6
+28 <==> -28OK. Well I was just trying to figure out how you came up with this (incorrect) statement.
Yeah, you definitely canât divide the later year by 4 and subtract.
I think adding or subtracting 28 always works unless you hit a non-leap-year century (1900, 2100, 2200, etc) in between. You donât always need to go forward / back that far, but you can. The centuries that arenât leap years disrupt the pattern though.
Sort of like how multiplying two denominators always gives you a common denominator, even if itâs not the lowest.
You can; but that algorithm isnât nearly as straight forward as the âforwardâ algorithm.
I agree that going forward, 28 years works except for starting with a non-leap-year century.
| Start | Add (Next Remainder) | Cum Add (Next-Next Remainder) | Cum Add (Next^3 Remainder) |
|---|---|---|---|
| 1 | +6 (3) | +17 (2) | +28 (1) |
| 2 | +11 (1) | +17 (3) | +28 (2) |
| 3 | +11 (2) | +22 (1) | +28 (3) |
In the case of a non-leap-year century, youâll get to +6 (and resulting remainder of 2) and this cycle will now follow the second row of the above table (+6, +17, +23, +34).
you guys are such 
s
you know, a nerd contest among actuariesâŚ
-sigh-